#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
#include <stdlib.h>
#include <assert.h>
#include <string.h>
模擬實現(xiàn)strlen 函數(shù)(求字符串長度)的實現(xiàn) 函數(shù)原型:size_t strlen(const char* str);
int mystrlen(const char* str){// 計數(shù)器方式int i = 0;assert(*str != NULL); // 使用斷言操作進行合法性檢驗while (*str){ i ; str ;}return i;// 不允許創(chuàng)建臨時變量的計數(shù)器方式(遞歸)if (*str == '\0') return 0;else return 1 mystrlen(str 1);// 指針-指針的方式char* p = str;while (*p!='\0'){ p ;}return p - str;}
模擬實現(xiàn)strcpy函數(shù)(將后一個字符串的內(nèi)容拷貝到前一個字符串中),原型:char*
strcpy(char* destination,const char* source);
char* mystrcpy(char* dest, const char* src){assert(dest&&src);// 方法一char* ret = dest;while ((*dest = *src )){ ;}return ret;// 方法二int i = 0;for (i = 0; src[i] != '\0'; i ){ dest[i] = src[i];}dest[i] = '\0';return dest;}
模擬實現(xiàn)strcat函數(shù)(字符串拼接),函數(shù)原型:char* strcat(char* destination,const char* source);
char* mystrcat(char* dest, const char* src){// 合法性檢驗assert(dest&&src);// 方法一char* ret = dest;while (*dest){ dest ;}while ((*dest = *src )){ ;}return ret;// 找到dest的結(jié)束位置int i = 0;for (i = 0; dest[i] != '\0'; i );// 將src拷貝到dest的結(jié)束位置int j = 0;for (j = 0; src[j] != '\0';i , j ){ dest[i] = src[j];}dest[i] = '\0';return dest;}
模擬實現(xiàn)strstr函數(shù)(用于判斷字符串str2是否是str1的子串),
如果是,則該函數(shù)返回str2在str1中首次出現(xiàn)的地址;否則,返回NULL。
函數(shù)原型:char* strstr(const cahr *,const char *);
char* my_strstr(const char *str1, const char *str2){char *cp = (char* )str1;char *substr = (char *)str2;assert(str1&&str2);char *s1 = NULL;if (*str2 == '\0'){ return NULL;}while (*cp){ s1 = cp; substr = str2; while (*s1 && *substr && (*s1 == *substr)) { s1 ; substr ; } if (*substr == '\0') return cp; cp ;}}
模擬實現(xiàn)strchr函數(shù),原型: char *strchr(const char *str, int c) 在參數(shù) str 所指向的字符串中搜索第一次出現(xiàn)字符 c(一個無符號字符)的位置。
char *my_strchr(const char *str, int c){assert(str);while (*str && (*str != (char)c)){ str ; if ((char)c == *str) { return (char*)str; } return NULL;}}
模擬實現(xiàn)strcmp函數(shù)(比較兩個字符串的大?。?,函數(shù)原型:int strcmp(const char str,const char dst)
int my_strcmp(const char *str1, const char *str2){assert(str1&&str2);while (*str1 == *str2){ if (*str1 == '\0') return 0; }return *str1 - *str2;}
模擬實現(xiàn)memcpy,函數(shù)原型:void *memcpy(void *str1, const void *str2, size_t n) 從存儲區(qū) str2 復(fù)制 n 個字符到存儲區(qū) str1
void* my_memcpy(void* dest, void* src, size_t n){void* ret = dest;char* str1 = (char*)dest;char* str2 = (char*)src;assert(dest);assert(src);while (n--){ *str1 = *str2 ;}return ret;}
模擬實現(xiàn)memmove函數(shù),原型: void *memmove(void *str1, const void *str2, size_t n) 從 str2 復(fù)制 n 個字符到 str1
void *my_memmove(void *str1, const *str2, size_t n){void *ret = str1;assert(str1&&str2);if (str1 <= str2 || ((char *)str1 >= (char *)str2 n)){ while (n--) { *(char *)str1 = *(char *)str2; str1 = (char *)str1 1; str2 = (char *)str2 1; }}else{ str1 = (char *)str1 n - 1; str2 = (char *)str2 n - 1; while (n--) { *(char *)str1 = *(char *)str2; str1 = (char *)str1 - 1; str2 = (char *)str2 - 1; }}return(ret);}
測試代碼:
int main(){ int i = 0;int arr1[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };int arr2[10] = { 0 };int arr3[10] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };my_memcpy(arr2, arr1, sizeof(arr1));my_memmove(arr3 5, arr3 4, 3 * sizeof(int));for (i = 0; i < 10; i ){ printf("%d ", arr2[i]);}printf("\n");for (i = 0; i < 10; i ){ printf("%d ", arr3[i]);}printf("\n");//printf("%d\n", my_strcmp(str1, str2));/*char *str = "hello bit ke ji";printf("%s\n", my_strchr(str,' j'));*//*char *str1 = "WHEN YOU HERE PEOPLE SING";char *str2 = "PEOPLE";char *pl;printf("%s\n", my_strstr(str1, str2));*//*printf("%s\n", mystrcat(str1, str2));printf("%s\n", mystrcpy(str1, str2));printf("%d\n", mystrlen(str1));*/system("pause");return 0;}
來源:http://www.icode9.com/content-4-134601.html